Shell脚本监控网站页面正常打开情况

现在单位为了省钱，我用了shell脚本，简单的写了一个监控。通过curl一个固定页面的200状态码，如果是200，就说网站是正常的,如果不是200就自动重启网站，然后发邮件到QQ邮箱。自己在上QQ的同时，通过微信也可以收到报警，不但可以收到报警，还可以解决问题。基本上也可以解决web的故障。

#! /bin/bash

source /etc/profile

A="web is Good !"

ip=`ifconfig eth0 | grep "inet addr" | awk -F "[: ]+" '{print $4}'`

tt1=`curl -I -s http://xx.8x.18x.xx:1657/product/pro_detail_-rg000785.shtml | head -1 | cut -d " " -f2`

Process=`ps -ef | grep java | egrep  "tomcat1" | awk -F " " '{print $2}'`

if [ $tt1 = "200" ]

  then

  echo "$A" >>/home/taoyake/scripts/website-error.`date +%F`.log

else

  /opt/tomcat1/bin/shutdown.sh

  cd /opt/tomcat1/work/Catalina/

  rm -rf localhost

  kill -9 $Process

  /opt/tomcat1/bin/startup.sh

  echo "1657 is reload." >>/home/taoyake/scripts/website-error.`date +%F`.log

  echo "1657 is reload." | mail -s "website-1657" "505065674@qq.com"

fi

more /home/taoyake/scripts/reload_website-1658.sh 

#! /bin/bash

source /etc/profile

B="1658 is Good !"

ip=`ifconfig eth0 | grep "inet addr" | awk -F "[: ]+" '{print $4}'`

tt1=`curl -I -s http://xx.xx.183.xx:1658/product/pro_detail_-rg000785.shtml | head -1 | cut -d " " -f2`

Process=`ps -ef | grep java | egrep  "tomcat2" | awk -F " " '{print $2}'`

if [ $tt1 = "200" ]

  then

  echo "$B" >>/home/taoyake/scripts/website-1658-access.`date +%F`.log

else

  /opt/tomcat2/bin/shutdown.sh

  cd /opt/tomcat2/work/Catalina/

  rm -rf localhost

  kill -9 $Process

  /opt/tomcat2/bin/startup.sh

  echo "1658 is reload." >>/home/taoyake/scripts/website-1658-error.`date +%F`.log

  echo "1658 is reload." | mail -s "website-1658" "505065674@qq.com"

fi

[root@web ~]# crontab -l

*/10 * * * * /usr/sbin/ntpdate time.windows.com >/dev/null 2>&1

*/5 * * * * /bin/sh /home/taoyake/scripts/reload_website.sh >/dev/null 2>&1

*/5 * * * * /bin/sh /home/taoyake/scripts/reload_website-1658.sh >/dev/null 2>&1

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